Ok, I'm looking for a little help here. I'm trying to convert a 5gal recipe to a 15 gal one. I've been using Ray Daniels "Designing Great Beers" and have succeeded in changing the malt bill. However, the calculations for the hops are driving me crazy. Any suggestions? PAG
Just seeking help with the math? 5 -> 15 gallons...can't you just multiply everything by three, or am I missing something?
Hey PAGeisler, you might find you'll get more replies if you post this thread in the Homebrewing section of the site. There might be some replies on here, but I think you will have more luck over there. http://www.beeradvocate.com/community/forums/homebrewing.8/ The link for convenience. Good luck!
No can do. As in any cooking recipe it is more a matter of ratio than quantity. Thanks ,I'll see Thanks, I'll give that a try.
Roughly speaking, you can pretty much multiply everything by 3, except for water. That's because water and wort losses are equipment dependent, and not batch size dependent. Now...to be more exact, the water volumes (average amount of wort in the kettle) will also affect your hop utilization slightly, so if you want to scale your hops more precisely, your best bet would be software that does the scaling for you. But if you don't want to get that complicated, just multiply your hops by 3.
http://www.realbeer.com/hops/bcalc_js.html As long as you know the target IBUs of the original 5 gal recipe, just adjust the hops needed here to get around the same IBUs for 15 gal
I do know the target IBUs of the first recipe. My problem is using the the formulas given to achieve the difference. From what I've read the aroma hops must be calculated first as they must be subtracted from the total of the bittering hops.Still have that glazed look in my eyes I'm afraid.
